Close to part 2?
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1 changed files with 45 additions and 9 deletions
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@ -42,28 +42,61 @@ proc squidBingo(inputLines: seq[string]): int =
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boards.add board
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echo boards
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for n in calledNumbers:
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echo n
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for b in boards.mitems():
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for i, e in b.entries:
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if n == e:
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# TODO: why can't I add here but I can add on 46?!
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b.checked.add i
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echo b.entries, b.checked
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if b.isBoardWinning():
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var entriesSum = 0
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for i, v in b.entries:
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if not (i in b.checked): entriesSum += v.parseInt()
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else: echo &"{i} {v}"
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echo &"{entriesSum} * {n} = {entriesSum * n.parseInt()}"
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return entriesSum * n.parseInt()
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return 0
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proc loseSquidBingo(inputLines: seq[string]): int =
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var input: seq[string] = inputLines
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let calledNumbers: seq[string] = input[0].split ','
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input.delete 0..1
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# construct boards
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var boards: seq[Board]
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var board: Board = Board(entries: @[], checked: @[])
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for l in input:
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if l.strip() == "":
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boards.add board
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board = Board(entries: @[], checked: @[])
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continue
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board.entries.add [l[0..1], l[3..4], l[6..7], l[9..10], l[12..13]].mapIt(it.strip())
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boards.add board
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for n in calledNumbers:
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echo &"Calling {n}..."
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var removeBoards: seq[int] = @[]
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for bbi, b in boards.mpairs():
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for i, e in b.entries:
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if n == e:
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b.checked.add i
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if b.isBoardWinning():
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echo "Board Win"
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if (boards.len() - removeBoards.len()) < 2:
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echo &"Last Board: {board}"
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var entriesSum = 0
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for i, v in b.entries:
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if not (i in b.checked): entriesSum += v.parseInt()
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return entriesSum * n.parseInt()
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else:
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removeBoards.add(bbi)
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echo &"Removing {removeBoards.len()} board(s) of {boards.len()}..."
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for i in removeBoards:
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boards.delete(i, i)
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return 0
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let input = 4.loadInput()
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time("squidBingo part 1"): echo input.squidBingo()
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# time("squidBingo part 1"): echo input.squidBingo()
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# time("loseSquidBingo part 2"): echo input.loseSquidBingo()
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when not defined(release):
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static:
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@ -86,4 +119,7 @@ when not defined(release):
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18 8 23 26 20
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22 11 13 6 5
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2 0 12 3 7""".split('\n')
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doAssert testInput.squidBingo() == 4512
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# doAssert testInput.squidBingo() == 4512
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let r = testInput.loseSquidBingo()
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echo r
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doAssert r == 1924
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